7x^2-196x-3200=0

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Solution for 7x^2-196x-3200=0 equation:



7x^2-196x-3200=0
a = 7; b = -196; c = -3200;
Δ = b2-4ac
Δ = -1962-4·7·(-3200)
Δ = 128016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{128016}=\sqrt{144*889}=\sqrt{144}*\sqrt{889}=12\sqrt{889}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-196)-12\sqrt{889}}{2*7}=\frac{196-12\sqrt{889}}{14} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-196)+12\sqrt{889}}{2*7}=\frac{196+12\sqrt{889}}{14} $

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